Electrostatics – Stage 2 (Page 4)
Applications of Gauss’s Law
1️⃣ Electric Field due to Infinite Plane Sheet
Consider an infinite plane sheet with uniform surface charge density σ.
Choose a pill-box Gaussian surface crossing the sheet.
- Field is perpendicular to sheet
- Same magnitude on both sides
2EA = σA / ε₀
E = σ / (2ε₀)
⚠️ Important: Field is independent of distance from sheet.
2️⃣ Field due to Two Parallel Infinite Sheets
- Same sign → fields cancel inside
- Opposite sign → fields add inside
E = σ / ε₀ (between plates)
This is the basis of the parallel-plate capacitor.
3️⃣ Electric Field due to Charged Spherical Shell
(a) Outside the shell (r > R)
Gaussian surface: sphere of radius r.
E(4πr²) = Q / ε₀
E = 1/(4πε₀) · Q / r²
👉 Behaves like a point charge at center.
(b) Inside the shell (r < R)
Enclosed charge = 0
E = 0
⚠️ Very important IIT concept: Field inside hollow conductor is zero.
4️⃣ Electric Field due to Uniformly Charged Solid Sphere
(a) Outside the sphere (r > R)
Same as point charge:
E = 1/(4πε₀) · Q / r²
(b) Inside the sphere (r < R)
Enclosed charge:
Qenc = Q · (r³
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