Gravitation – Board Exam Questions & Answers

Stage 2 • Page 2 • Long Answer Questions


Q1. Derive the expression for acceleration due to gravity on the surface of Earth.

According to Newton’s law of gravitation, the gravitational force between Earth and a body of mass m on its surface is:

F = G (Mm / R²)

This force produces acceleration g in the body:

F = mg

Equating the two expressions:

mg = G (Mm / R²)

Cancelling m on both sides:

g = GM / R²

Thus, acceleration due to gravity depends on the mass and radius of Earth.


Q2. Derive the expression for variation of g with height above Earth’s surface.

At a height h above Earth’s surface, distance from Earth’s centre is (R + h).

Acceleration due to gravity at height h:

gh = GM / (R + h)²

Dividing by g = GM / R²:

gh / g = (R / (R + h))²

For small heights (h ≪ R):

gh ≈ g (1 − 2h/R)

Hence, acceleration due to gravity decreases with increase in height.


Q3. Explain variation of acceleration due to gravity with depth.

At a depth d below Earth’s surface, distance from Earth’s centre is (R − d).

Acceleration due to gravity at depth d is:

gd = g (1 − d/R)

  • g decreases linearly with depth
  • g becomes zero at Earth’s centre

This happens because gravitational pull from all directions cancels at the centre.


Q4. Distinguish between mass and weight.

Mass Weight
Quantity of matter Gravitational force
Constant Variable
Scalar Vector
kg N

Q5. Derive the expression for escape velocity of a body from Earth.

Escape velocity is the minimum velocity required to take a body from Earth’s surface to infinity with zero velocity.

Initial energy = Final energy

At Earth’s surface:

Total Energy = ½ m ve² − GMm / R

At infinity:

Total Energy = 0

Equating:

½ m ve² = GMm / R

Thus:

ve = √(2GM / R) = √(2gR)


Exam Writing Tips

  • Always start derivations from basic laws
  • Write formulas clearly and boxed if possible
  • Mention assumptions (h ≪ R, no air resistance)
  • Use correct units and symbols

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