Gravitation – IIT/JEE Advanced Rank Booster Problems

Phase 2 • Page 10 • High-Frequency Previous Paper Concepts


Problem 23: Variation of g with Depth & Height (Combined)

Q: At what depth below Earth’s surface and at what height above surface does acceleration due to gravity become half of its surface value?

Solution:

  • Below surface: gd = g (1 − d/R)
  • Above surface: gh = g (R² / (R + h)²)

Half g condition:

  • d = R/2
  • h = (√2 − 1)R

Exam Trick: Depth → linear relation Height → inverse square relation


Problem 24: Satellite Orbit Change Due to Impulse

Q: A satellite moving in circular orbit receives a small tangential impulse. What is new orbit?

Answer:

  • Orbit becomes elliptical
  • Point of impulse becomes perigee or apogee
  • Angular momentum conserved

IIT Insight: Any sudden velocity change → ellipse.


Problem 25: Energy of Satellite at Different Points

Q: Compare total energy of satellite at perigee and apogee.

Answer:

Total energy remains constant throughout orbit.

Trap: Speed changes, but total energy does NOT.


Problem 26: Escape Velocity from Height h

Q: Find escape velocity of a particle from height h above Earth.

Formula:

ve = √(2GM / (R + h))

Common Mistake: Using surface escape velocity blindly.


Problem 27: Geostationary Satellite Conditions

Q: Write conditions for a satellite to appear stationary from Earth.

  • Orbital period = 24 hours
  • Orbit in equatorial plane
  • Direction same as Earth’s rotation

Examiner Love: Conceptual + factual clarity.


Problem 28: Two Satellites at Different Radii

Q: Compare angular velocities of two satellites at radii r₁ and r₂.

ω ∝ 1 / r3/2

Shortcut: Larger orbit → slower angular speed.


MASTER FORMULA BLOCK (Must Remember)

  • vorbit = √(GM/r)
  • E = − GMm / (2r)
  • T² ∝ r³ (Kepler’s Law)
  • vescape = √(2GM/r)

EXAM STRATEGY FOR GRAVITATION

If problem involves orbit → use energy & angular momentum
If problem involves fall → use force & acceleration
Never mix both blindly


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