⚡ Electrostatics – Objective Questions
Page 2: Clearly Explained Solutions (JEE Level)
Q1. Electric field at the midpoint of +q and −q
Given:
- Two charges: +q and −q
- Distance between charges = d
- Midpoint is at d/2 from each charge
Concept Used:
Electric field due to a point charge:
E = (1 / 4πε₀) · (q / r²)
Step-by-Step Explanation:
- Field due to +q points away from +q
- Field due to −q points towards −q
- Both fields act in the same direction
Calculation:
Enet = 2 × (1 / 4πε₀) × q / (d/2)²
= (2q) / (4πε₀ d²)
Answer: Option C
JEE Trap: Fields do not cancel; directions matter.
Q2. Unit of Electric Flux
Concept:
Electric Flux Φ = E · A
Units:
- Electric Field (E) → N/C
- Area (A) → m²
Result: N·m²/C
Answer: Option B
Q3. Electric field inside a charged conducting shell
Concept: Electrostatic Equilibrium
- Electric field inside a conductor = 0
- Charges reside on the surface
- Any internal field would cause charge motion
Answer: Option C
Important: Result is independent of shell radius.
Q4. Law applicable only for symmetric charge distributions
Comparison:
- Coulomb’s Law → Always valid, complex
- Gauss’s Law → Powerful only for symmetry
Symmetry Types: Spherical, Cylindrical, Planar
Answer: Option B
Q5. Electric Flux – Multiple Correct
Using Gauss Law:
Φ = Qenclosed / ε₀
- A. Scalar quantity ✔
- B. Depends on enclosed charge ✔
- C. Depends on shape ✘
- D. Independent of external charges ✔
Correct Options: A, B, D
Q6. Conductor in electrostatic equilibrium
- Electric field inside = 0 ✔
- Charge on surface ✔
- Potential constant ✔
- Electric field maximum inside ✘
Correct Options: A, B, C
Q7. Assertion–Reason
Assertion: Electric field inside a conductor is zero (True)
Reason: Charges redistribute to cancel internal field (True)
Conclusion: Reason correctly explains assertion
Answer: Option A
Q8. Integer Type – Electric Flux
Given:
- Charge Q = 5 μC = 5 × 10⁻⁶ C
- ε₀ = 8.85 × 10⁻¹²
Calculation:
Φ = Q / ε₀
= (5 × 10⁻⁶) / (8.85 × 10⁻¹²)
= 5.65 × 10⁵ N·m²/C
Answer: 5.65 × 10⁵
🎯 JEE Key Takeaways
- Direction of electric field is crucial
- Flux depends only on enclosed charge
- Field can be zero while potential is not
- Gauss law is always true but not always useful
No comments:
Post a Comment