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⚡ Electrostatics – Objective Questions

Page 2: Clearly Explained Solutions (JEE Level)


Q1. Electric field at the midpoint of +q and −q

Given:

  • Two charges: +q and −q
  • Distance between charges = d
  • Midpoint is at d/2 from each charge

Concept Used:

Electric field due to a point charge:
E = (1 / 4πε₀) · (q / r²)

Step-by-Step Explanation:

  • Field due to +q points away from +q
  • Field due to −q points towards −q
  • Both fields act in the same direction

Calculation:

Enet = 2 × (1 / 4πε₀) × q / (d/2)²
= (2q) / (4πε₀ d²)

Answer: Option C

JEE Trap: Fields do not cancel; directions matter.


Q2. Unit of Electric Flux

Concept:

Electric Flux Φ = E · A

Units:

  • Electric Field (E) → N/C
  • Area (A) → m²

Result: N·m²/C

Answer: Option B


Q3. Electric field inside a charged conducting shell

Concept: Electrostatic Equilibrium

  • Electric field inside a conductor = 0
  • Charges reside on the surface
  • Any internal field would cause charge motion

Answer: Option C

Important: Result is independent of shell radius.


Q4. Law applicable only for symmetric charge distributions

Comparison:

  • Coulomb’s Law → Always valid, complex
  • Gauss’s Law → Powerful only for symmetry

Symmetry Types: Spherical, Cylindrical, Planar

Answer: Option B


Q5. Electric Flux – Multiple Correct

Using Gauss Law:

Φ = Qenclosed / ε₀

  • A. Scalar quantity ✔
  • B. Depends on enclosed charge ✔
  • C. Depends on shape ✘
  • D. Independent of external charges ✔

Correct Options: A, B, D


Q6. Conductor in electrostatic equilibrium

  • Electric field inside = 0 ✔
  • Charge on surface ✔
  • Potential constant ✔
  • Electric field maximum inside ✘

Correct Options: A, B, C


Q7. Assertion–Reason

Assertion: Electric field inside a conductor is zero (True)

Reason: Charges redistribute to cancel internal field (True)

Conclusion: Reason correctly explains assertion

Answer: Option A


Q8. Integer Type – Electric Flux

Given:

  • Charge Q = 5 μC = 5 × 10⁻⁶ C
  • ε₀ = 8.85 × 10⁻¹²

Calculation:

Φ = Q / ε₀
= (5 × 10⁻⁶) / (8.85 × 10⁻¹²)
= 5.65 × 10⁵ N·m²/C

Answer: 5.65 × 10⁵


🎯 JEE Key Takeaways

  • Direction of electric field is crucial
  • Flux depends only on enclosed charge
  • Field can be zero while potential is not
  • Gauss law is always true but not always useful

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