🔥 Kinetic Theory of Gases – Stage 3 (Page 9)
Numerical Problems, Graphs & Assertion–Reason (IIT-JEE)
🔢 Numerical 1 (RMS Speed – Direct)
Find RMS speed of O2 at 300 K. (M = 32 × 10-3 kg/mol, R = 8.314)
vrms = √(3RT/M)
= √(3 × 8.314 × 300 / 0.032)
Answer: ≈ 484 m/s
IIT Tip: Temperature ↑ ⇒ speed ↑ as √T
🔢 Numerical 2 (Pressure from Molecular Data)
Gas has density ρ and RMS speed vrms. Find pressure.
P = (1/3) ρ vrms2
IIT Trick: Direct formula, no temperature needed
📈 Graph Question 1
Graph of Pressure vs Mean Square Speed is:
- A) Straight line through origin
- B) Parabola
- C) Hyperbola
- D) Exponential
Correct: A
Because P ∝ ⟨c²⟩
📈 Graph Question 2
Graph of Average Speed vs Temperature is:
- A) Linear
- B) Square root
- C) Cubic
- D) Constant
Correct: B
⚖️ Assertion–Reason 1
Assertion (A): RMS speed of gas molecules increases with temperature.
Reason (R): Average kinetic energy of gas molecules increases with temperature.
- A) Both A and R true, R explains A
- B) Both true, R not explanation
- C) A true, R false
- D) A false, R true
Correct: A
⚖️ Assertion–Reason 2
Assertion: At constant temperature, pressure of gas depends on molecular mass.
Reason: Heavier molecules move slower.
Correct: D
Pressure depends only on temperature and number density.
🔍 Conceptual Numerical (Advanced)
At same temperature:
vrms, H₂ : vrms, O₂ = ?
= √(MO₂ / MH₂) = √(32 / 2) = 4
Answer: 4 : 1
⚠️ IIT Exam Traps (Page 9)
- Using linear instead of √T relation
- Confusing ⟨c⟩, crms, cmp
- Ignoring constant condition
- Wrong graph interpretation
🧠 Rank Booster Strategy
- Convert word problems → formula instantly
- Memorize proportional relations
- Practice assertion–reason logic
🏁 Stage 3 – Page 9 Completed (Almost Done!)
📚 IIT–JEE Physics Complete Library (Class XI)
Curated for IIT-JEE Advanced Aspirants
Concepts • Numericals • Objective Questions • Revision Capsules
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