Lesson 7 – Momentum & Collisions
Phase 1: IIT / JEE Solved Problems
Page 4 – Challenging Mixed Problems
Problems on this page demand strong algebra, clear physical reasoning, and proper use of restitution. These are typical of upper JEE Main / entry JEE Advanced.
Problem 1 (Elastic Collision – Ratio Type)
Two particles of masses 2 kg and 1 kg move along the same line with velocities 4 m/s and 1 m/s respectively. If the collision is elastic, find their velocities after collision.
Concept Used: Momentum + Energy conservation
Momentum before = 2×4 + 1×1 = 9
Elastic collision (e = 1):
v₂ − v₁ = u₁ − u₂ = 3
Solving equations:
v₁ = 2 m/s
v₂ = 5 m/s
Problem 2 (Restitution Based)
A ball is dropped vertically on a smooth floor from a height h. If the coefficient of restitution between ball and floor is e, find the height to which the ball rises after first bounce.
Key Insight: Vertical collision → use speeds just before and after impact
Speed just before impact = √(2gh)
Speed after rebound = e√(2gh)
Height after rebound = e²h
Problem 3 (Impulse + Variable Direction)
A particle moving with velocity 6 m/s strikes a wall at right angles and rebounds with velocity 4 m/s. Find the impulse imparted to the particle.
Concept Used: Impulse = change in momentum
Initial momentum = m×6
Final momentum = m×(−4)
Impulse = −4m − 6m = −10m
Magnitude of impulse = 10m N·s
Problem 4 (Conceptual – Trick Question)
Can kinetic energy ever increase during a collision? If yes, give an example.
Answer:
Yes. In an explosion or collision involving internal energy release, kinetic energy can increase while momentum remains conserved.
Example: Explosion of a bomb at rest.
🧠 IIT Strategy Notes (Page 4)
✔ Vertical collisions behave like 1-D collisions
✔ Heights after bounce depend on e² (VERY important)
✔ Impulse problems need careful sign handling
✔ Energy increase is possible only due to internal forces
👉 Next: Phase 1 – Page 5 (Final Phase-1 Wrap + Transition to Tough Problems)

No comments:
Post a Comment