Simple Harmonic Motion (SHM) – IIT Tough Objective Questions

Stage-1 | Page-1 | JEE Advanced Level


Q1. A particle executes SHM with amplitude A. At what displacement will its kinetic energy be equal to its potential energy?

Options:
A) A/√2 B) A/2 C) A/√3 D) A
Answer: A
Explanation:
K = U ⇒ ½mω²(A² − x²) = ½mω²x² ⇒ x = A/√2

Q2. In SHM, velocity is maximum at:

Options:
A) Extreme position B) Mean position C) At x = A/2 D) At x = A/√2
Answer: B
Key Concept: Restoring force = 0 → acceleration = 0 → velocity maximum.

Q3. The time taken by a particle to go from x = A/2 to x = −A/2 in SHM is:

Options:
A) T/6 B) T/4 C) T/3 D) T/2
Answer: C
Hint:
Use phase angle: x = A sinθ θ₁ = 30°, θ₂ = −30° → Δθ = 60° = π/3 ⇒ Time = T/3

Q4. In SHM, acceleration is proportional to:

Options:
A) Velocity B) Square of displacement C) Displacement D) Square of velocity
Answer: C
Formula: a = −ω²x

Q5. If the total energy of a particle in SHM is E, then its kinetic energy at displacement x is:

Options:
A) E − ½mω²x² B) ½mω²x² C) E + ½mω²x² D) Constant
Answer: A
Concept: K = E − U

✅ Stage-1 | Page-1 Completed

No comments:

Post a Comment

  📘 IIT–JEE Physics Complete Master Library (Class XI & XII) Concepts • Problems • Advanced Applications • Thinking Skill...