Simple Harmonic Motion (SHM) – Tough Objective Questions

Stage-1 | Page-2 | JEE Advanced Level


Q6. A particle performs SHM with amplitude A. The ratio of time taken to move from x = 0 to x = A/2 and from x = A/2 to x = A is:

Options:
A) 1 : 1 B) 1 : 2 C) 2 : 1 D) 1 : 3
Answer: C
Explanation:
Time ∝ phase change 0 → A/2 ⇒ θ = 0° → 30° A/2 → A ⇒ 30° → 90° Ratio = 30 : 60 = 1 : 2 ⇒ Inverse speed ⇒ 2 : 1

Q7. The total energy of a particle executing SHM is E. At what displacement does the kinetic energy become 3E/4?

Options:
A) A/2 B) A/√2 C) A/√3 D) A/4
Answer: A
Explanation:
K = E − ½mω²x² = 3E/4 ⇒ x² = A²/4 ⇒ x = A/2

Q8. In SHM, the magnitude of acceleration is maximum at:

Options:
A) Mean position B) Extreme position C) x = A/2 D) Everywhere same
Answer: B
Formula: a = ω²A (maximum)

Q9. The phase difference between displacement and velocity in SHM is:

Options:
A) 0 B) π/2 C) π D) π/4
Answer: B
Concept: Velocity leads displacement by π/2.

Q10. A particle in SHM crosses the mean position with speed v. What is its speed at displacement A/2?

Options:
A) v B) v/2 C) v√3/2 D) v/√2
Answer: C
Explanation:
v = ωA vx = ω√(A² − x²) = ω√(A² − A²/4) = ωA√3/2

✅ Stage-1 | Page-2 Completed

No comments:

Post a Comment

  📘 IIT–JEE Physics Complete Master Library (Class XI & XII) Concepts • Problems • Advanced Applications • Thinking Skill...