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Stage 2 – Page 4 : Standing Waves on a String (One End Fixed, One End Free)
1️⃣ Boundary Conditions
In this case:
- One end is fixed → Node
- Other end is free → Antinode
Golden Rule:
A free end always behaves like an antinode.
2️⃣ Allowed Standing Wave Patterns
Only those wave patterns are allowed which satisfy:
- Node at fixed end
- Antinode at free end
Because of this restriction, not all harmonics are possible.
3️⃣ Allowed Wavelengths
λₙ = 4L / (2n − 1)
where n = 1, 2, 3, ...
Key Observation:
Only odd harmonics are present.
4️⃣ Allowed Frequencies
fₙ = (2n − 1) × (v / 4L)
n = 1 → Fundamental frequency
5️⃣ Fundamental Mode (First Harmonic)
- n = 1
- λ₁ = 4L
- Lowest frequency
f₁ = v / 4L
6️⃣ Comparison with String Fixed at Both Ends
| Property | Both Ends Fixed | One End Free |
|---|---|---|
| Harmonics | All | Only odd |
| Fundamental λ | 2L | 4L |
| Fundamental f | v / 2L | v / 4L |
7️⃣ Numerical Example
Question:
A string of length 0.5 m has one end fixed and the other free.
Wave speed is 200 m/s. Find fundamental frequency.
Solution:
f₁ = v / 4L = 200 / (4 × 0.5)
f₁ = 100 Hz
8️⃣ Important JEE Points
- Even harmonics are absent
- Free end = maximum displacement
- Frequency ratios → 1 : 3 : 5
9️⃣ Common Mistakes
- Using 2L instead of 4L
- Including even harmonics
- Misidentifying node/antinode
🔟 Next Page Preview
- Standing waves in air columns
- Open pipe vs closed pipe
Stage 2 – Page 4 Completed Successfully ✅
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