IIT / JEE ADVANCED – TOUGH PROBLEMS

Oscillations & Simple Harmonic Motion (SET–2)


Problem 1: Piecewise Spring Constant (Classic JEE Trap)

A particle of mass m is attached to a spring. For extension, spring constant = k. For compression, spring constant = 4k. The particle oscillates with very small amplitude. Find the time period.

Solution:

For small oscillations, motion depends on restoring force near mean position. Effective spring constant:

keff = (k + 4k)/2 = 5k/2

Time period:

T = 2π √(m / keff) = 2π √(2m / 5k)

Answer: T = 2π √(2m / 5k)

Examiner Thinking: Students wrongly use either k or 4k instead of averaging.


Problem 2: SHM + Energy Conservation

A particle in SHM has maximum speed vmax. Find the speed when displacement is A/√3.

Solution:

v = ω√(A² − x²)

x = A/√3 ⇒ x² = A²/3

v = ωA √(1 − 1/3) = ωA √(2/3)

Since vmax = ωA,

v = vmax √(2/3)

Answer: v = vmax √(2/3)


Problem 3: Time from Energy Condition

In SHM, find the time taken for kinetic energy to change from E/4 to E/2.

Solution:

KE = E(1 − x²/A²)

For KE = E/4:

1 − x₁²/A² = 1/4 ⇒ x₁²/A² = 3/4 ⇒ x₁ = (√3/2)A

For KE = E/2:

1 − x₂²/A² = 1/2 ⇒ x₂²/A² = 1/2 ⇒ x₂ = A/√2

Use phase method:

x = A cosθ

cosθ₁ = √3/2 ⇒ θ₁ = π/6 cosθ₂ = 1/√2 ⇒ θ₂ = π/4

Δθ = π/4 − π/6 = π/12

Δt = (T / 2π)(π / 12) = T / 24

Answer: T / 24


Problem 4: Moving Support (Advanced)

A mass attached to a spring oscillates vertically. If the support of the spring moves upward with constant velocity, the nature of oscillation is:

Answer: Still SHM

Reason:

Constant velocity does not introduce acceleration. Restoring force remains proportional to displacement.

Hidden Concept: Acceleration of support matters, not velocity.


Problem 5: SHM Validity Test

Which force can produce SHM for small oscillations?

  • A) F = −kx
  • B) F = −kx³
  • C) F = −k sin x
  • D) F = −k/x

Correct Answer: C

Because for small x, sin x ≈ x ⇒ restoring force ∝ x


Problem 6: Acceleration Comparison

Compare acceleration at displacement A/2 and A/√2.

Solution:

a = ω²x

a₁ / a₂ = (A/2) / (A/√2) = √2 / 2

Answer: a(A/2) < a(A/√2)


SET–2 FINAL TAKEAWAYS

  • Small oscillation ≠ full motion
  • Average stiffness near mean position
  • Energy method > equations
  • Phase saves time in JEE Advanced
  • Velocity of support does not break SHM

IIT / JEE Tough Problems – SET–2 Completed ✅

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