IIT / JEE ADVANCED – EXTREME TOUGH PROBLEMS

Oscillations & Simple Harmonic Motion (SET–4)


Problem 1: SHM in Non-Inertial Frame (Angular Acceleration)

A mass m attached to a spring of spring constant k is placed on a smooth table. The table rotates with constant angular acceleration α. Find the nature of motion for small oscillations.

Solution:

In rotating frame, pseudo forces include:

  • Centrifugal force ∝ r
  • Coriolis force ∝ velocity

Coriolis force does not affect restoring force. Centrifugal force shifts equilibrium position.

Restoring force about new mean is still proportional to displacement.

Answer: Motion remains SHM with same time period

Examiner Insight: Only forces proportional to displacement affect SHM frequency.


Problem 2: SHM with Slowly Varying Spring Constant

In a spring–mass system, the spring constant varies slowly with time as: k(t) = k₀(1 − βt), where βt ≪ 1. How does the time period change?

Solution:

T(t) = 2π √(m / k(t))

As k decreases with time, T increases gradually.

Answer: Time period increases slowly with time

JEE Trap: Students assume time period constant because change is slow.


Problem 3: Maximum Power Transfer in SHM

At what position during SHM is instantaneous power maximum?

Solution:

Power P = Fv = (kx)(ω√(A² − x²))

To maximize P, differentiate or use symmetry:

Maximum power occurs at:

x = A / √2

Answer: x = A / √2

Elite Insight: Power depends on both force and velocity → balance point.


Problem 4: SHM with Time-Dependent Force

A particle is subjected to force: F = −kx + F₀ sin(ωt). Describe the long-term motion.

Solution:

The system shows:

  • Natural SHM
  • Forced oscillation

After transients die out, steady-state motion dominates.

Answer: Forced oscillation with driving frequency


Problem 5: Limiting Case Analysis (Advanced)

For SHM, consider ω → 0. What does motion approach?

Solution:

ω → 0 ⇒ restoring force → 0

System approaches uniform motion.

Answer: Uniform motion

IIT Trick: Always test limiting cases to verify reasoning.


Problem 6: Energy Loss per Cycle (Damping)

In lightly damped SHM, energy lost per cycle is proportional to:

  • A) Amplitude
  • B) Velocity
  • C) Square of amplitude
  • D) Time period

Correct Answer: C

Energy ∝ A², hence loss ∝ A².


SET–4 FINAL TAKEAWAYS

  • Pseudo forces often shift mean, not frequency
  • Slow variation ≠ no variation
  • Power maximization uses balance logic
  • Limiting cases reveal physics instantly
  • Damping affects energy faster than time period

IIT / JEE Tough Problems – SET–4 Completed ✅

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🔹 Simple Harmonic Motion (SHM) — Core Series

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🔹 Simple Harmonic Motion (SHM) — Extended Series (30–56)

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