Rotational Motion – Phase 1 (Page 2)
Previous IIT-JEE / JEE Main Problems (Moderate Level)
These problems are selected from previous papers and standard JEE patterns. They require concept + calculation + correct method.
PYQ-7 (IIT-JEE)
A uniform disc of mass M and radius R rolls without slipping down an incline. Find the ratio of its translational kinetic energy to rotational kinetic energy.
Solution:
Translational KE = ½ Mv²
Rotational KE = ½ Iω²
For disc: I = ½ MR²
Rolling condition: v = ωR
Rotational KE = ½ × ½ MR² × (v²/R²) = ¼ Mv²
Ratio = (½ Mv²) : (¼ Mv²) = 2 : 1
Answer: 2 : 1
PYQ-8 (JEE Main)
A particle moves in a circular path of radius r with speed v. Its angular momentum about the centre is:
Solution:
Angular momentum L = r × p
Here p = mv and r ⟂ v
So, L = mvr
Answer: mvr
PYQ-9 (IIT-JEE)
A solid sphere and a solid cylinder of same mass and radius roll down an incline without slipping. Which reaches first?
Solution:
Acceleration for rolling body:
a = g sinθ / (1 + I/MR²)
Solid sphere: I = 2/5 MR² → denominator = 1 + 2/5 = 7/5
Solid cylinder: I = ½ MR² → denominator = 1 + ½ = 3/2
Smaller denominator ⇒ larger acceleration
Answer: Solid sphere reaches first
PYQ-10 (AIEEE)
A torque τ acts on a body of moment of inertia I. The angular acceleration produced is:
Solution:
Newton’s second law for rotation:
τ = Iα
So, α = τ / I
Answer: α = τ / I
PYQ-11 (JEE Main)
A wheel is rotating with angular velocity ω. If external torque is zero, which quantity remains constant?
Solution:
Using relation:
τ = dL/dt
τ = 0 ⇒ angular momentum remains constant
Answer: Angular momentum
PYQ-12 (Board + JEE Pattern)
Why does a ring roll slower than a disc on an incline?
Solution:
Ring has larger moment of inertia:
Iring = MR²
Idisc = ½ MR²
Larger I ⇒ smaller acceleration
Answer: Due to larger moment of inertia
Exam Tips (Phase 1 – Page 2)
✔ Always write rolling condition v = ωR
✔ Compare I/MR² to decide speed
✔ Conservation laws reduce calculation
✔ Memorize standard moments of inertia
Next: Phase 1 – Page 3 (Higher-Moderate IIT/JEE Problems)
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