Rotational Motion – Phase 2 (Page 6)

IIT-JEE Tough Problems (Advanced Level)

These problems are concept-heavy and appear in IIT-JEE Advanced / Tough JEE Main sections. Focus on logic, not speed.


TP-1 (IIT-JEE Advanced)

A uniform rod of length L and mass M is free to rotate in a horizontal plane about one end. A particle of mass m strikes the free end perpendicular to the rod with velocity v and sticks to it. Find the angular velocity just after collision.

Solution:

No external torque about hinge ⇒ angular momentum conserved.

Initial angular momentum:
Li = m v L

Final moment of inertia:
I = ML²/3 + mL²

Using Li = Iω:

ω = (m v L) / (ML²/3 + mL²)

Answer: ω = m v / (L(M/3 + m))


TP-2 (IIT-JEE)

A disc of mass M and radius R is rotating freely with angular speed ω. A ring of same mass and radius is gently placed on it concentrically. Find final angular speed.

Solution:

No external torque ⇒ angular momentum conserved.

Initial: Li = (½MR²)ω

Final moment of inertia:
I = ½MR² + MR² = 3/2 MR²

ωf = (½MR² ω) / (3/2 MR²)

Answer: ωf = ω / 3


TP-3 (JEE Advanced)

A cylinder rolls down an incline of angle θ. Find the frictional force acting on it.

Solution:

Equations:
Mg sinθ − f = Ma
fR = Iα

For cylinder: I = ½MR²,   α = a/R

Solving:
a = (2/3) g sinθ

f = Mg sinθ − Ma

Answer: f = (1/3) Mg sinθ


TP-4 (IIT-JEE Advanced)

A flywheel of moment of inertia I rotates at ω. Energy stored is used to lift a mass m slowly. Find maximum height reached.

Solution:

Initial energy = rotational KE

½ Iω² = mgh

Answer: h = Iω² / (2mg)


TP-5 (IIT-JEE)

Two discs of same radius but different masses rotate with same angular speed. Which has greater angular momentum?

Logic:

Angular momentum L = Iω

Heavier disc → larger I → larger L

Answer: Heavier disc


HOW TO HANDLE TOUGH IIT PROBLEMS

✔ Identify conservation law first
✔ Choose axis carefully
✔ Do NOT rush into equations
✔ Write I clearly before substitution
✔ Trust physics, not memory


Next: Phase 2 – Page 7 (Even Tougher Multi-Concept Problems)

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