Rotational Motion – Phase 1 (Page 4)
IIT-JEE / JEE Main – Numerical Traps & Variations
This page focuses on how IIT examiners twist simple concepts. Every problem below is inspired by previous year papers.
PYQ-18 (IIT-JEE – Trap Question)
Two bodies of same mass and radius roll down an incline. One is a solid disc, the other is a ring. Which statement is correct?
Correct Method:
Acceleration for rolling:
a = g sinθ / (1 + I / MR²)
Disc: I = ½MR² → denominator = 1.5
Ring: I = MR² → denominator = 2
Conclusion: Disc reaches first
Examiner Trap: Many students compare mass instead of I/MR².
PYQ-19 (JEE Main – Axis Trap)
Moment of inertia of a rod is different when rotated about:
Correct Reasoning:
Moment of inertia depends on axis of rotation.
About centre: I = ML²/12
About end: I = ML²/3
Key Point: Same body → different I due to axis
Common Mistake: Students memorize only one formula.
PYQ-20 (IIT-JEE – Energy vs Torque)
A disc rolls without slipping. Which method is best to find its speed?
Correct Method:
✔ Use energy conservation, not F = ma
Mgh = ½Mv² + ½Iω²
Why? Energy method avoids friction force calculation.
PYQ-21 (JEE Main – Angular Momentum Trap)
A rotating platform slows down when a man walks towards the centre. Why?
Correct Logic:
No external torque → angular momentum conserved
L = Iω = constant
As I decreases → ω increases
Result: Platform speeds up
Trap: Students wrongly apply torque equation.
PYQ-22 (IIT-JEE – Rolling + Friction)
In pure rolling, friction:
Correct Understanding:
• Friction provides torque
• But point of contact has zero displacement
Conclusion: Work done by friction = 0
EXAMINER’S FAVORITE TRAPS (Must Remember)
✔ Forgetting axis of rotation
✔ Confusing angular velocity with angular momentum
✔ Using force equations instead of energy
✔ Ignoring rolling condition v = ωR
✔ Memorizing without understanding I/MR² ratio
SMART SHORTCUT (JEE Rank Booster)
For rolling problems, compare I/MR² only. Smaller value → faster motion.
Next: Phase 1 – Page 5 (Mixed Numericals + Speed Tricks)
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