Rotational Motion – Phase 1 (Page 3)
Higher-Moderate IIT-JEE / JEE Main Problems (Solved)
These problems combine rolling + energy + torque + conservation laws. They are very common in JEE Main and older IIT-JEE papers.
PYQ-13 (IIT-JEE)
A uniform disc rolls without slipping down an incline of height h. Find its speed at the bottom.
Solution:
Use conservation of energy:
Potential energy = Translational KE + Rotational KE
Mgh = ½Mv² + ½Iω²
For disc: I = ½MR², ω = v/R
Mgh = ½Mv² + ½ × ½MR² × (v²/R²)
Mgh = ½Mv² + ¼Mv² = ¾Mv²
v² = (4/3)gh ⇒ v = √(4gh/3)
Answer: v = √(4gh/3)
PYQ-14 (JEE Main)
A rod of length L and mass M is hinged at one end and allowed to rotate freely from horizontal position. Find angular acceleration just after release.
Solution:
Torque about hinge:
τ = Mg × (L/2)
Moment of inertia about one end:
I = ML²/3
Using τ = Iα:
Mg(L/2) = (ML²/3)α
α = 3g / (2L)
Answer: α = 3g / (2L)
PYQ-15 (IIT-JEE)
A disc is rotating freely. A small mass is gently placed on its rim. What happens to angular velocity?
Solution:
No external torque ⇒ angular momentum conserved
Initial: Li = Iω Final: Lf = (I + mr²)ω'
Iω = (I + mr²)ω'
ω' < ω
Conclusion: Angular velocity decreases
PYQ-16 (AIEEE)
A wheel rolls without slipping. If its centre moves with speed v, what is the kinetic energy of the wheel?
Solution:
Total KE = Translational KE + Rotational KE
KE = ½Mv² + ½Iω²
Using rolling condition: ω = v/R
Answer: KE = ½Mv² + ½I(v²/R²)
PYQ-17 (JEE Main)
Why is a flywheel used in engines?
Solution:
Flywheel has large moment of inertia
⇒ Stores large rotational kinetic energy ⇒ Maintains uniform angular speed
Answer: To store energy and reduce speed fluctuations
Phase-1 High-Scoring Strategy
✔ Prefer energy conservation over force equations
✔ Identify correct axis before using torque
✔ Write I clearly (half marks saver)
✔ Rolling ⇒ translation + rotation both
Next: Phase 1 – Page 4 (Previous IIT-JEE Numerical Traps & Variations)
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