Rotational Motion – Phase 2 (Page 9)
Ultra-Tough Mixed Problems + Examiner Traps
This page completes Phase 2. Problems here are designed to break partial understanding and reward true IIT-level clarity.
TP-16 (IIT-JEE Advanced)
A solid sphere rolls down an incline and then enters a horizontal rough surface. Eventually it comes to rest. Which statement is correct?
Thinking:
• On incline → rolling with friction
• On rough horizontal → friction does negative work
Both translational and rotational KE decrease.
Answer: Both translational and rotational motion stop due to friction.
Examiner Trap: Assuming rolling continues forever.
TP-17 (IIT-JEE Advanced)
A disc and a sphere of same mass and radius rotate with same angular speed. Which has greater rotational kinetic energy?
Method:
Rotational KE = ½ Iω²
Disc: I = ½MR²
Sphere: I = 2/5MR²
Answer: Disc (larger moment of inertia)
TP-18 (IIT-JEE Advanced)
A rotating disc has angular momentum L. Its rotational kinetic energy is proportional to:
Logic:
K = L² / (2I)
Answer: Inversely proportional to moment of inertia.
Trap: Many assume larger I ⇒ larger energy (WRONG).
TP-19 (IIT-JEE Advanced)
A man stands at the edge of a rotating platform holding dumbbells. He pulls them inward. What changes?
Correct Analysis:
No external torque ⇒ angular momentum conserved
Angular velocity increases
Rotational kinetic energy increases
Answer: KE increases (work done by man)
TP-20 (IIT-JEE Advanced – Conceptual)
Why is it easier to balance a bicycle when it is moving?
Reason:
Rotating wheels have angular momentum
They resist change in orientation (gyroscopic effect)
Answer: Due to angular momentum stability.
PHASE-2 MASTER RULES (Very Important)
✔ Angular momentum > Linear momentum (in sudden events)
✔ Check where friction acts (work or torque?)
✔ Compare I/MR² quickly
✔ Energy may increase if internal work is done
✔ Never assume rolling unless stated
PHASE 2 COMPLETED ✅
Next: Phase 3 – Exam Mastery
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