Rotational Motion – Phase 1 (Page 5)
Mixed Numericals + Speed Solving Tricks
This page combines rolling motion, energy, torque, and angular momentum. Each problem includes a fast approach used by toppers.
PYQ-23 (JEE Main)
A solid cylinder of mass M and radius R rolls without slipping with speed v. Find its total kinetic energy.
Fast Method:
Total KE = Translational KE + Rotational KE
= ½Mv² + ½Iω²
For solid cylinder: I = ½MR², ω = v/R
KE = ½Mv² + ¼Mv² = ¾Mv²
Answer: ¾Mv²
PYQ-24 (IIT-JEE)
A disc and a ring roll down an incline of same height. Find ratio of their speeds at bottom.
Shortcut:
Use energy conservation:
v² ∝ 1 / (1 + I/MR²)
Disc: I/MR² = ½
Ring: I/MR² = 1
vdisc : vring = √(2/3) : √(1/2)
Result: Disc reaches faster
PYQ-25 (JEE Main)
A wheel starts rolling from rest without slipping. Which force is responsible for angular acceleration?
Concept:
Static friction provides torque about centre.
Answer: Static friction
PYQ-26 (IIT-JEE)
A rotating disc suddenly breaks into two equal parts. What happens to angular velocity?
Method:
Check external torque → zero
Apply angular momentum conservation.
Since I decreases → ω increases.
Conclusion: Angular velocity increases
PYQ-27 (JEE Main)
Why is angular velocity maximum at centre when a man moves inward on a rotating platform?
Fast Explanation:
No external torque → L = Iω = constant
I decreases → ω increases
Answer: Due to conservation of angular momentum
TOPPER SPEED TRICKS (Very Important)
✔ Prefer energy over force equations
✔ Compare I/MR², not I directly
✔ Rolling ⇒ write v = ωR immediately
✔ No torque ⇒ angular momentum conserved
✔ Memorize KE fractions for disc, ring, sphere
COMMON TIME-WASTERS
❌ Writing full force equations unnecessarily
❌ Forgetting axis of rotation
❌ Ignoring rotational KE
❌ Over-calculating simple ratios
Phase 1 COMPLETED ✅
Next: Phase 2 – IIT/JEE Tough Problems
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Advanced exam-oriented thinking series focusing on traps, execution, pressure handling, and topper strategies.
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