Objective Type Questions – SHM (Page 9)

Focus: PYQ Pattern • Tricky Logic • Examiner Traps

Level: Very Tough (JEE Advanced)

                                    

Shm poster used in iit material


Instructions:
Each question has one correct answer. Avoid assumptions. Think in phase, symmetry, and energy.
Q81.
A particle performs SHM. At which position is the product of velocity and acceleration maximum?

Answer: x = A/√2
Logic: v·a = ω³x√(A² − x²)
Q82.
The ratio of maximum kinetic energy to maximum potential energy in SHM is:

Answer: 1
Concept: Total energy is constant
Q83.
A particle in SHM crosses the mean position with speed v₁ and crosses x = A/2 with speed v₂. Find v₁/v₂.

Answer: 2/√3
Q84.
In SHM, potential energy becomes equal to kinetic energy at:

Answer: x = A/√2
Q85.
Time taken by SHM particle to move from x = 0 to x = A/2 is:

Answer: T/12
Method: Use phase angle sinθ = x/A
Q86.
Which graph represents SHM correctly?
(A) a vs x straight line through origin
(B) v vs x straight line
(C) x vs t straight line
(D) a vs t straight line

Correct Answer: A
Q87.
If displacement is doubled, kinetic energy becomes:

Answer: Cannot be determined (depends on initial position)
Trap: KE depends on remaining amplitude
Q88.
Which quantity changes sign at mean position?
(A) Velocity
(B) Acceleration
(C) Displacement
(D) Energy

Correct Answer: C
Q89.
The phase difference between velocity and acceleration in SHM is:

Answer: π/2
Q90.
A particle performs SHM. If time period is T, then time taken to go from +A to −A is:

Answer: T/2

Examiner Reminder:
• Energy questions → think symmetry
• Time questions → phase method
• Graph questions → slope & sign

End of Objective Page 9

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