🌡️ Thermodynamics – Stage 2

Page 3 : First Law in Multi-Process & Mixed Systems

JEE Advanced loves problems where a system undergoes multiple processes. One wrong step → entire answer collapses.

1️⃣ First Law – Universal Backbone

ΔU = Q − W
(Always true, regardless of process)
👉 First Law is applied process-wise in multi-step questions

2️⃣ Multi-Step Process Strategy (Toppers’ Method)

For each step:
  1. Identify the process
  2. Find W (work)
  3. Find ΔU
  4. Use ΔU = Q − W
👉 Final values = algebraic sum of all steps

3️⃣ Common Multi-Process Combination (Very High Yield)

Isothermal → Isochoric → Isobaric
  • Step 1: ΔU = 0
  • Step 2: W = 0
  • Step 3: Both Q & W present
⚠ Many students incorrectly assume same formula for all steps

4️⃣ Total Internal Energy Change

ΔU depends only on:

Initial & Final Temperature
ΔU = nCᵥ (T₂ − T₁)
👉 Path is irrelevant for ΔU

5️⃣ Heat Calculation – Stepwise Only

Total heat:
Qtotal = Q₁ + Q₂ + Q₃ + …
❌ Never use one formula for whole process

6️⃣ Cyclic + Non-Cyclic Hybrid Problems

If system returns to initial state:
  • ΔU = 0
  • Q = W
👉 Check if final temperature equals initial temperature

7️⃣ Sign Convention – Silent Killer

  • Heat absorbed → Q +ve
  • Heat rejected → Q −ve
  • Expansion → W +ve
  • Compression → W −ve
⚠ One sign error = wrong option

8️⃣ IIT Advanced Thinking Pattern

Ask yourself:
  • Which step contributes maximum work?
  • Where is temperature changing?
  • Is any step redundant?

✅ Stage 2 – Page 3 Complete
👉 Next: Stage 2 – Page 4 : Heat Capacities, Cp vs Cv & Graphical Traps

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