🔥 Thermodynamics – Stage 3
Page 6 : Multi-Concept PYQs (Hidden Trap Edition)
These questions combine 2–3 concepts and test thinking speed under pressure.
PYQ 1️⃣ : Isochoric + Isothermal Combo
A gas is heated at constant volume, then allowed to expand isothermally to original pressure.
Logic:
Step-1 (Isochoric): W = 0, Q = ΔU
Step-2 (Isothermal): ΔU = 0, Q = W
Step-1 (Isochoric): W = 0, Q = ΔU
Step-2 (Isothermal): ΔU = 0, Q = W
❌ Treating entire process as isothermal
PYQ 2️⃣ : Cyclic Process Energy Trap
Gas undergoes a closed cycle with net work done.
ΔU = 0 ⇒ Qnet = Wnet
❌ Assuming zero heat because cycle ends at same state
PYQ 3️⃣ : Free Expansion + Ideal Gas
Ideal gas expands freely in vacuum.
Q = 0, W = 0 ⇒ ΔU = 0 ⇒ T constant
❌ Thinking expansion always causes cooling
PYQ 4️⃣ : Entropy + Reversibility
Two identical bodies at different temperatures exchange heat.
ΔStotal > 0 ⇒ Irreversible
❌ Forgetting total entropy, checking only system
PYQ 5️⃣ : PV Graph + Thermodynamics
Straight line on P-V graph from (P₁,V₁) to (P₂,V₂).
Work = area under curve (Trapezium)
❌ Using W = PΔV blindly
PYQ 6️⃣ : Adiabatic Temperature Trap
Rapid expansion of gas in insulated cylinder.
Q = 0 ⇒ ΔU = −W ⇒ Temperature decreases
❌ Assuming insulation means constant temperature
PYQ 7️⃣ : Heat Engine Logic Test
Engine absorbs Q₁, rejects Q₂.
Efficiency = 1 − Q₂/Q₁
❌ Using Carnot formula without temperature data
PYQ 8️⃣ : Degrees of Freedom Trap
Same heat supplied to monoatomic and diatomic gas.
ΔT ∝ 1/f
❌ Assuming equal temperature rise
PYQ 9️⃣ : Entropy Zero Fallacy
Reversible adiabatic process.
ΔS = 0 (only here!)
❌ Extending this to irreversible adiabatic
PYQ 🔟 : Final State Deception
Same initial & final states ≠ same work/heat
✅ Stage 3 – Page 6 Completed
➡️ Next: Stage 3 – Page 7 (Full JEE Advanced Mixed PYQ Drill)
➡️ Next: Stage 3 – Page 7 (Full JEE Advanced Mixed PYQ Drill)
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