🔥 Thermodynamics – Stage 3

Page 9 : Graph-Based & Multi-Concept Problems (JEE Advanced)

In JEE Advanced, graphs test interpretation, not memory. Wrong area or wrong slope = wrong answer.

Graph Problem 1️⃣ : P–V Diagram

A gas undergoes a cyclic process shown in a P–V graph.
What does the enclosed area represent?
✔ Net work done in one cycle ✔ Clockwise → Work done by gas ✔ Anticlockwise → Work done on gas

Graph Problem 2️⃣ : T–V Graph

A straight line on T–V graph for an ideal gas.
❌ Not isothermal ❌ Not adiabatic ✔ Only equation-based path

Graph Problem 3️⃣ : P–T Graph

Straight line passing through origin in P–T graph.
✔ Constant volume process ✔ Slope ∝ number of moles

Graph Problem 4️⃣ : Area Trap

Area under P–V curve between V₁ and V₂.
✔ Represents work ❌ Area under T–V or P–T has no direct physical meaning

Multi-Concept 1️⃣ : Isothermal + First Law

Gas expands isothermally from V₁ to V₂.
✔ ΔU = 0 ✔ Q = W = nRT ln(V₂/V₁)

Multi-Concept 2️⃣ : Adiabatic Graph Slope

Compare slopes of isothermal and adiabatic curves at same point.
✔ Adiabatic curve is steeper ✔ |dP/dV|adiabatic > |dP/dV|isothermal

Multi-Concept 3️⃣ : Free Expansion

Gas expands into vacuum.
✔ W = 0 ✔ Q = 0 ✔ ΔU = 0 ✔ Entropy increases

Multi-Concept 4️⃣ : Heat Engine Graph

Efficiency depends on area enclosed.
✔ Larger area ≠ higher efficiency ✔ Depends on Qin and Qout

JEE PYQ Insight 💡

Most wrong answers come from:
  • Wrong graph area
  • Confusing slope with area
  • Ignoring direction of cycle

✅ Stage 3 – Page 9 Completed
➡️ Next: Stage 3 – Page 10 (JEE Advanced Mixed Integer + Conceptual Numericals)

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