🔥 Thermodynamics – Stage 2

Page 5 : Adiabatic Process & Poisson’s Equations (JEE Advanced Core)

Adiabatic process is the backbone of thermodynamics problems. One wrong assumption → entire solution collapses.

1️⃣ What is an Adiabatic Process?

Adiabatic Process: A thermodynamic process in which no heat exchange takes place.
👉 Q = 0
👉 Temperature can change
👉 Work is done at the expense of internal energy

2️⃣ Key Adiabatic Condition (JEE Favorite)

PVγ = Constant
✔ Valid only for ideal gas
✔ Process must be quasi-static

3️⃣ Poisson’s Equations (Must Memorize)

  • PVγ = constant
  • TVγ−1 = constant
  • TγP1−γ = constant
⚠ Examiner mixes these deliberately — choose carefully.

4️⃣ Temperature Change in Adiabatic Process

During expansion → Temperature decreases
During compression → Temperature increases
👉 No heat leaves or enters 👉 Energy change comes purely from work

5️⃣ Work Done in Adiabatic Process

Work Done:
W = (P₁V₁ − P₂V₂) / (γ − 1)
✔ Formula valid only for ideal gas
✔ Must not use isothermal work formula

6️⃣ P–V Graph Comparison (High Yield)

For same initial state:
  • Isothermal curve → flatter
  • Adiabatic curve → steeper
❌ Students often reverse this in exams

7️⃣ JEE Advanced Trap Zone

  • Fast process ≠ adiabatic always
  • Insulated system ≠ adiabatic if non-quasi static
  • PVγ = constant applies only to ideal gas
  • Q = 0 does NOT mean T = constant

8️⃣ One-Line Thinking Rule

If heat exchange is zero → think ADIABATIC → apply Poisson relations.

✅ Stage 2 – Page 5 Completed
➡️ Next: Stage 2 – Page 6 : Isothermal vs Adiabatic (Comparative Mastery & PYQ Traps)

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