🔥 Thermodynamics – Stage 2
Page 5 : Adiabatic Process & Poisson’s Equations (JEE Advanced Core)
Adiabatic process is the backbone of thermodynamics problems.
One wrong assumption → entire solution collapses.
1️⃣ What is an Adiabatic Process?
Adiabatic Process:
A thermodynamic process in which no heat exchange takes place.
👉 Q = 0
👉 Temperature can change
👉 Work is done at the expense of internal energy
👉 Temperature can change
👉 Work is done at the expense of internal energy
2️⃣ Key Adiabatic Condition (JEE Favorite)
PVγ = Constant
✔ Valid only for ideal gas
✔ Process must be quasi-static
✔ Process must be quasi-static
3️⃣ Poisson’s Equations (Must Memorize)
- PVγ = constant
- TVγ−1 = constant
- TγP1−γ = constant
⚠ Examiner mixes these deliberately — choose carefully.
4️⃣ Temperature Change in Adiabatic Process
During expansion → Temperature decreases
During compression → Temperature increases
During compression → Temperature increases
👉 No heat leaves or enters
👉 Energy change comes purely from work
5️⃣ Work Done in Adiabatic Process
Work Done:
W = (P₁V₁ − P₂V₂) / (γ − 1)
W = (P₁V₁ − P₂V₂) / (γ − 1)
✔ Formula valid only for ideal gas
✔ Must not use isothermal work formula
✔ Must not use isothermal work formula
6️⃣ P–V Graph Comparison (High Yield)
For same initial state:
- Isothermal curve → flatter
- Adiabatic curve → steeper
❌ Students often reverse this in exams
7️⃣ JEE Advanced Trap Zone
- Fast process ≠ adiabatic always
- Insulated system ≠ adiabatic if non-quasi static
- PVγ = constant applies only to ideal gas
- Q = 0 does NOT mean T = constant
8️⃣ One-Line Thinking Rule
If heat exchange is zero → think ADIABATIC → apply Poisson relations.
✅ Stage 2 – Page 5 Completed
➡️ Next: Stage 2 – Page 6 : Isothermal vs Adiabatic (Comparative Mastery & PYQ Traps)
➡️ Next: Stage 2 – Page 6 : Isothermal vs Adiabatic (Comparative Mastery & PYQ Traps)
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